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Find the square root of a number with any precision

function bcgetscale(){
    return strlen(bcadd(1,0))-2;
}

//Version 0.2 of BCRoot
//By Chao XU
//From www.webdevlogs.com
//Change Log: It uses a lot bcsqrt() to make the speed fast
//fix a small decimal bug, where the last decimal could be wrong
       
function bcroot($a, $n, $scale='default'){
    $default = bcgetscale();//Get the scale
    if($scale == 'default'){
        $scale = $default;//use default scale
    }
    if($n & ($n-1)){//check if $n is the power of 2, return 0 if is
        //decbin is the reason this function can't have number
        //larger than 2^31
        $bin = decbin($n);
        $i = strlen($bin)-1;
        $pow = 0;
        while($i){
            if($bin[$i]==='0'){
                ++$pow; –$i;
            }else{
                break;
            }
        }
        $n = bcdiv($n, bcpow(2, $pow),0);
       //now use Newton’s method to find the number
        bcscale($scale+15);
        $x = 1;
        $k = 0;
        $limit = ceil(log($scale+15)/log(2))+1;
        while($k<$limit){
            $t1 = bcdiv(1,$n);
            $t21 = bcmul(bcsub($n,1),$x);
            $t22 = bcdiv($a,bcpow($x, $n-1));
            $t2 = bcadd($t21,$t22);
            $x = bcmul($t1, $t2);
            ++$k;
        }
        $i = 0;
        while($i < $pow){
            $x = bcsqrt($x,$scale+3);
            ++$i;
        }
        bcscale($default);
        return bcadd($x,0,$scale);
    }else{
    //here use many bcsqrt, because this is FAST
        $i = 0;
        $pow = log($n)/log(2);
        while($i < $pow){
            $a = bcsqrt($a,$scale+3);
            ++$i;
        }
        return bcadd($a,0,$scale);
    }
}

And now use it

$the_number = 3;
$the_nth_root = 12;
$the_precision = 30;
bcroot($the_number, $the_nth_root, $the_precision);
//returns 1.095872691135244380160019128072.
//Which is the 12th root of 3
 

Topics: PHP | Submitter: admin

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